26 lines
479 B
Markdown
26 lines
479 B
Markdown
$$f' = \dfrac{e^{-5x} * cos(3x)-e^{-5x}*[cos(3x)]'}{cos^2(3x)}$$
|
|
|
|
$${ df(x)} over { dx } = { { e^{(-5x)'} } * cos( 3x) - e^{-5x} * [ cos(3x) ]' } over { cos^2(3x) } = { e^{-5x}*(-5 * cos(3x) 3sen(-3x))} over { cos^2(3x) } }$$
|
|
|
|
|
|
## 2.
|
|
$$
|
|
\large
|
|
y=x^3 \cdot(\sqrt{x} + x^2)
|
|
$$
|
|
$$
|
|
y=x^3 \cdot(x^{\frac{1}{2}} + x^2)
|
|
$$
|
|
$$
|
|
y=x^{\frac{3}{2}} + x^5
|
|
$$
|
|
$$
|
|
y=x^{\frac{7}{2}} + x^5
|
|
$$
|
|
$$
|
|
y'=\frac{7}{2} \cdot x^{\frac{5}{2}} + 5\cdot x^4
|
|
$$
|
|
$$
|
|
y'=\small \dfrac{7}{2}. x^2\sqrt{x}+5x^4
|
|
$$
|