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Álvaro Antônio de Lacerda Rosário 2025-01-05 11:59:17 -03:00
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Física/1. Tópicos Fundamentais/Exercícios/Cinemática/Movimento uniforme.md
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@ -277,8 +277,8 @@ $$
f'(t) &= 4,5 t ^2 \Rightarrow\\ f'(t) &= 4,5 t ^2 \Rightarrow\\
f'(\sqrt[3]{17,5}) &= 4,5 \cdot (\sqrt[3]{17,5}) ^2 \\ f'(\sqrt[3]{17,5}) &= 4,5 \cdot (\sqrt[3]{17,5}) ^2 \\
&= 4,5 \cdot \sqrt[3]{17,5^2} \\ &= 4,5 \cdot \sqrt[3]{17,5^2} \\
&= 4,5 \cdot \sqrt[3]{17,5^3 \cdot 17,5^{-1}} \\ &= 4,5 \cdot 17,5 \cdot \sqrt[3]{17,5^{-1}} \\
&= 4,5 \cdot 17,5^{-1} \\ &= 4,5 \cdot 17,5^3 \cdot 17,5^{\frac{3}{-1}} \\
&= 4,5 \cdot \dfrac{1}{17,5} \\ &= 4,5 \cdot \dfrac{1}{17,5} \\
&= \dfrac{4,5}{17,5} \\ &= \dfrac{4,5}{17,5} \\
&= 0,257142857 &= 0,257142857