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Álvaro Antônio de Lacerda Rosário 2025-01-02 21:06:03 -03:00
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37
Física/1. Tópicos Fundamentais/Exercícios/Cinemática/Movimento uniforme e uniformemente variado.md
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@ -64,26 +64,7 @@ $\LARGE v_m = 68,819751381 km/h$
$\LARGE v_{m_{ida}} = 72,4 km/h$
$\LARGE v_{m_{volta}} = 68,82 km/h$
$\LARGE \Delta S * 2 = (v_{m_{ida}} + v_{m_{volta}}) * (t_1 + t_2)$
$\LARGE \Delta S * 2 = 141,22km/h * (t_1 + t_2)$
$\LARGE 141,22km/h = \dfrac{t_1 + t_2}{\Delta S * 2}$
$\LARGE 141,22km/h = \dfrac{\dfrac{\Delta S}{v_1 \cdot 2} + \dfrac{\Delta S}{v_2 \cdot 2}}{\Delta S * 2}$
$\LARGE 141,22km/h = \dfrac{\Delta S / 2 \cdot (\dfrac{1}{v_1} + \dfrac{1}{v_2})}{\Delta S * 2}$
$\LARGE 141,22km/h = \dfrac{\dfrac{1}{v_1} + \dfrac{1}{v_2}}{4}$
$\LARGE 141,22km/h = \dfrac{\dfrac{1}{v_1} + \dfrac{1}{v_2}}{4}$
$\LARGE 141,22km/h = \dfrac{\dfrac{v_2}{v_1 \cdot v_2} + \dfrac{v_1}{v_1 \cdot v_2}}{4}$
$\LARGE 141,22km/h = \dfrac{\dfrac{v_1 + v_2}{v_1 \cdot v_2}}{4}$
$\LARGE 141,22km/h = \dfrac{\dfrac{v_1 + v_2}{v_1 \cdot v_2}}{4}$
---
$\LARGE v_m = \dfrac{v_{m_{ida}} * t_{ida} + v_{m_{volta}} * t_{volta}}{t_{ida} + t_{volta}}$
$\LARGE v_m = \dfrac{2d}{t_{ida} + t_{volta}}$
@ -97,10 +78,22 @@ $\LARGE v_m = \dfrac{2}{\dfrac{1}{v_{ida}} + \dfrac{1}{v_{volta}}}$
$\LARGE v_m = \dfrac{2}{\dfrac{1}{72,4} + \dfrac{1}{68,82}}$
$\LARGE \dfrac{1}{v_m * 2} = \dfrac{1}{72,4} + \dfrac{1}{68,82}$
$\LARGE \dfrac{1}{v_m} = \dfrac{\dfrac{1}{72,4} + \dfrac{1}{68,82}}{2}$
$\LARGE \dfrac{2}{v_m} = \dfrac{1}{72,4} + \dfrac{1}{68,82}$
$\LARGE \dfrac{2}{v_m} = \dfrac{68,82}{68,82 * 72,4} + \dfrac{72,4}{68,82 * 72,4}$
$\LARGE \dfrac{2}{v_m} = \dfrac{68,82}{4982,568} + \dfrac{72,4}{4982,568}$
$\LARGE \dfrac{2}{v_m} = \dfrac{141,22}{4982,568}$
$\LARGE \dfrac{v_m}{2} = \dfrac{4982,568}{141,22} = 35,282311287$
$\LARGE v_m = 35,282311287 * 2 = 70,56 km/h$
$\LARGE \dfrac{1}{v_m * 2} = \dfrac{68,82}{68,82 * 72,4} + \dfrac{72,4}{68,82 * 72,4}$
$\LARGE \dfrac{1}{v_m * 2} = \dfrac{68,82}{4982,568} + \dfrac{72,4}{4982,568}$