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Álvaro Antônio de Lacerda Rosário 2025-01-05 11:24:17 -03:00
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Física/1. Tópicos Fundamentais/Exercícios/Cinemática/Movimento uniforme.md
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@ -266,7 +266,11 @@ x(3) = 9,75 + 1,5 \cdot 8 = 50,25cm \\
1,50t ^3 = 26,25 \Rightarrow \\ 1,50t ^3 = 26,25 \Rightarrow \\
t^3 = 17,5 \Rightarrow \\ t^3 = 17,5 \Rightarrow \\
t = \sqrt[3]{17,5} t = \sqrt[3]{17,5}
\\
f'(t) = 4,5 t ^2 \Rightarrow \\
f'(\sqrt[3]{17,5}) = 4,5 \cdot (\sqrt[3]{17,5}) ^2 = 4,5 \cdot \sqrt[3]{17,5^2} \Rightarrow \\
f'(3) = 4,5 \cdot \sqrt[3]{17,5^3 \cdot 17,5^{-1}} \Rightarrow \\
f'(3) = 4,5 \cdot \sqrt[3]{17,5^3 \cdot 17,5^{-1}} \Rightarrow \\
\end{gathered} \end{gathered}
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