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Álvaro Antônio de Lacerda Rosário 2025-01-05 12:38:51 -03:00
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Física/1. Tópicos Fundamentais/Exercícios/Cinemática/Movimento uniforme.md
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@ -270,7 +270,6 @@ $$
1,50t ^3 &= 26,25 \Rightarrow \\
t^3 &= 17,5 \Rightarrow \\
t &= \sqrt[3]{17,5} \\
t &= \sqrt[3]{\dfrac{1750}{1000}} = \dfrac{\sqrt[3]{1750}}{\sqrt[3]{1000}} \\
\end{align*}
$$
$$