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Álvaro Antônio de Lacerda Rosário 2025-01-03 18:39:56 -03:00
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Física/1. Tópicos Fundamentais/Exercícios/Cinemática/Movimento uniforme e uniformemente variado.md
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@ -123,11 +123,11 @@ $x(4) = 3*4 - 4*4^2 + 4^3 = \LARGE 12$
### 📄 Resolução 9.2 ### 📄 Resolução 9.2
$\Delta S = S_f - S_0$ $\Delta S = S_f - S_0$
$\Large \Delta S (t_0, t_f) = x(t_f) - x(t_0)$ $\Large \Delta S (t_0, t_f) = x(t_f) - x(t_0)$
$\Delta S (0, 2) = -2m - 0m = \Large -2m$ $\Delta S (0, 2) = -2m - 0m = \Large -2m$
$\Delta S (0, 4) = 12m - 0m = \Large 12m$ $\Delta S (0, 4) = 12m - 0m = \Large 12m$
🧐 **Resposta:** $-2m$ e $12m$ respectivamente 🧐 **Resposta:** $-2m$ e $12m$ respectivamente
@ -136,12 +136,12 @@ $\Delta S (0, 4) = 12m - 0m = \Large 12m$
$v = \dfrac{\Delta S}{\Delta t}$ $v = \dfrac{\Delta S}{\Delta t}$
$v(t_0, t_f) = \dfrac{\Delta S (t_0, t_f)}{t_f - t_0}$ $v(t_0, t_f) = \dfrac{\Delta S (t_0, t_f)}{t_f - t_0}$
$\LARGE v(t_0, t_f) = \dfrac{x(t_f) - x(t_0)}{t_f - t_0}$ $\LARGE v(t_0, t_f) = \dfrac{x(t_f) - x(t_0)}{t_f - t_0}$
$v(0, 4) = \dfrac{x(4) - x(0)}{4s - 0s} = \dfrac{12m}{4s} = 3m/s$ $v(0, 4) = \dfrac{x(4) - x(0)}{4s - 0s} = \dfrac{12m}{4s} = 3m/s$
$v(0, 3) = \dfrac{x(3) - x(0)}{3s - 0s} = \dfrac{0m}{3s} = 0m/s$ $v(0, 3) = \dfrac{x(3) - x(0)}{3s - 0s} = \dfrac{0m}{3s} = 0m/s$
🧐 **Resposta:** $3m/s$ e $0m/s$ respectivamente 🧐 **Resposta:** $3m/s$ e $0m/s$ respectivamente